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x^2-6x+9=60
We move all terms to the left:
x^2-6x+9-(60)=0
We add all the numbers together, and all the variables
x^2-6x-51=0
a = 1; b = -6; c = -51;
Δ = b2-4ac
Δ = -62-4·1·(-51)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{15}}{2*1}=\frac{6-4\sqrt{15}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{15}}{2*1}=\frac{6+4\sqrt{15}}{2} $
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